Mesh analysis is used to find the voltages and currents in a circuit. Usually mesh analysis is employed when there are more than one meshes/loops and many voltage sources.
Procedure:
- Identify the number of meshes in a circuit.
- Assign the mesh currents. The assignment of mesh currents is arbitrary and consistent.
- Apply Kirchoff's Voltage Law (KVL) to all meshes and obtain the mesh equations.
- Solve the equations and obtain the mesh currents.
Mesh Analysis with Current Sources:
- If the current source is in only one mesh, then write KVL as usual and substitute value from the current source and solve.
- If current source is between two meshes, then eliminate the current source and element in series with it (like open circuiting the branch) and form a super mesh.
- Write KVL and solve the equations.
- Write Nodal equation for the node where these elements where eliminated.
- On solving all the equations mesh currents will be obtained.
Example:
Find the mesh/loop currents in the following circuit.
Find the mesh/loop currents in the following circuit.
The circuit has a current source in between two meshes. So we eliminate the current source and the resistor in series with it, to form a super mesh.
KVL for the super mesh,
–8 + 2i1 – 2i3 + 12i2 – 4i3 = 0 or i1 + 6i2 – 3i3 = 4 (1)
KVL for mesh 3,
8i3 – 2i1 – 4i2 = 0 or –i1 – 2i2 + 4i3 = 0 (2)
Kirchoff's Current Law (KCL) at node 0 in Fig. (a),
i1 = 4 + i2 i1 – i2 = 4
Solving (1) to (3) we obtain the mesh currents,
i1 = 4.632
A, i2 = 631.6
mA, i3 = 1.4736
A
Reference:
Fundamentals of Electric Circuits( Fifth Edition) by Charles K Alexander and Matthew N O Sadiku